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1948 New Hampshire gubernatorial election

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1948 New Hampshire gubernatorial election

← 1946 November 2, 1948 1950 →
 
Nominee Sherman Adams Herbert W. Hill
Party Republican Democratic
Popular vote 116,212 105,207
Percentage 52.21% 47.27%

County results
Adams:      50-60%      60-70%      70-80%
Hill:      50-60%      60–70%

Governor before election

Charles M. Dale
Republican

Elected Governor

Sherman Adams
Republican

The 1948 New Hampshire gubernatorial election was held on November 2, 1948. Republican nominee Sherman Adams defeated Democratic nominee Herbert W. Hill with 52.21% of the vote.

Primary elections

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Primary elections were held on September 14, 1948.[1]

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican Sherman Adams 39,094 83.59
Republican John R. McIntire 7,673 16.41
Total votes 46,767 100.00

General election

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Candidates

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Major party candidates

  • Sherman Adams, Republican
  • Herbert W. Hill, Democratic

Other candidates

  • Irma C. Otto, Progressive

Results

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1948 New Hampshire gubernatorial election[2]
Party Candidate Votes % ±%
Republican Sherman Adams 116,212 52.21%
Democratic Herbert W. Hill 105,207 47.27%
Progressive Irma C. Otto 1,152 0.52%
Majority 11,005
Turnout 222,571
Republican hold Swing

References

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  1. ^ a b Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved May 30, 2020.
  2. ^ Cook, Rhodes (November 5, 2013). America Votes 30: 2011-2012, Election Returns by State. ISBN 9781452290171. Retrieved May 30, 2020.